[Solution] [Manual] Charles K. Alexander, Matthew N. O. Sadiku - Funda…
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[Solution] [Manual] Charles K. Alexander, Matthew N. O. Sadiku - Fundamentals of Electric Circuits, 2nd Edition - Solutions Manual-McGraw-Hill ~ (2002)
솔루션,전기전자,솔루션
순서
[Solution] [Manual] Charles K. Alexander, Matthew N. O. Sadiku - Fundamentals of Electric Circuits, 2nd Edition - Solutions Manual-McGraw-Hill ~ (2002)
Chapter 1, Solution 1 (a) q = 6.482x1xxx x [-1.602x10-19 C] = -0.10384 C (b) q = 1. 24x1xxx x [-1.602x10-19 C] = -0.19865 C (c) q = 2.46x1xxx x [-1.602x10-19 C] = -3.941 C (d) q = 1.628x1020 x [-1.602x10-19 C] = -26.08 C Chapter 1, Solution 2 (a) (b) (c) (d) (e) i = dq/dt = 3 mA i = dq/dt = (16t + 4) A i = dq/dt = (-3e-t + 10e-2t) nA i=dq/dt = 1200…(투비컨티뉴드 )
설명
[Solution] [Manual] Charles K. Alexander, Matthew N. O. Sadiku - Fundamentals of Electric Circuits, 2nd Edition - Solutions Manual-McGraw-Hill ~ (2002) , [Solution] [Manual] Charles K. Alexander, Matthew N. O. Sadiku - Fundamentals of Electric Circuits, 2nd Edition - Solutions Manual-McGraw-Hill ~ (2002)전기전자솔루션 , 솔루션
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